-6.5x+0.004x^2=-13x+0.012x^2

Solution for -6.5x+0.004x^2=-13x+0.012x^2 equation:

-6.5x+0.004x^2=-13x+0.012x^2

We move all terms to the left:

-6.5x+0.004x^2-(-13x+0.012x^2)=0

We get rid of parentheses

0.004x^2-0.012x^2+13x-6.5x=0

We add all the numbers together, and all the variables

-0.008x^2+6.5x=0

a = -0.008; b = 6.5; c = 0;
Δ = b2-4ac
Δ = 6.52-4·(-0.008)·0
Δ = 42.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.5)-\sqrt{42.25}}{2*-0.008}=\frac{-6.5-\sqrt{42.25}}{-0.016}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.5)+\sqrt{42.25}}{2*-0.008}=\frac{-6.5+\sqrt{42.25}}{-0.016}
$